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(D) Nitrobenzene contains a strongly electron-withdrawing $-NO_2$ group,which deactivates the benzene ring towards electrophilic substitution. Friedel

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No reaction occurs

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(D) Nitrobenzene contains a strongly electron-withdrawing $-NO_2$ group,which deactivates the benzene ring towards electrophilic substitution. Friedel-Crafts reactions (alkylation and acylation) do not occur with nitrobenzene because the $-NO_2$ group is a strong deactivating group and the catalyst $AlCl_3$ forms a complex with the nitrogen atom of the $-NO_2$ group,further deactivating the ring.

What is the product of the reaction between nitrobenzene and $CH_3Cl$ in the presence of anhydrous $AlCl_3$?

Similar Questions

Chlorobenzene $(X)$ when reacted with reagent '$A$' gets converted to phenol $(Y)$. The major product obtained from nitration of $X$ gets converted to $p$-nitrophenol $(Z)$ by reaction with reagent $B$. What are $A$ and $B$ respectively?

The product $(A)$ will be:

Which of the following are deactivating groups?
$-OH, -COCH_3, -NO_2, -NH_2, -Cl, -Br, -NHCOCH_3, -COOH$

Compare the rate of Electrophilic Substitution Reaction $(ESR)$ for the following compounds:

$A$ major component of Borsch reagent is obtained by reacting hydrazine hydrate with which of the following?

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