Class 11Chemistry8-3.Organic Chemistry : Purification and characterizationChemical analysis of organic compounds
MediumWhat is formed when an amine is fused with sodium metal?
- A$NaCN$
- B$NaN_3$
- C$NaSCN$
- D$NaNO_2$
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Similar Questions
Why is the Lassaigne's extract boiled with concentrated $HNO_3$ before testing for halogens?
Medium
View SolutionIn organic compounds,nitrogen is tested in Lassaigne's test as:
Medium
View SolutionMatch the compounds in List-$I$ with the observations in List-$II$,and choose the correct option.
List-$I$ List-$II$ $I$. Aniline $P$. Sodium fusion extract of the compound on boiling with $FeSO_4$,followed by acidification with conc. $H_2SO_4$,gives Prussian blue color. $II$. $o$-Cresol $Q$. Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color. $III$. Cysteine $R$. Addition of the compound to a saturated solution of $NaHCO_3$ results in effervescence. $IV$. Caprolactam $S$. The compound reacts with bromine water to give a white precipitate. $T$. Treating the compound with neutral $FeCl_3$ solution produces violet color.
| List-$I$ | List-$II$ |
|---|---|
| $I$. Aniline | $P$. Sodium fusion extract of the compound on boiling with $FeSO_4$,followed by acidification with conc. $H_2SO_4$,gives Prussian blue color. |
| $II$. $o$-Cresol | $Q$. Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color. |
| $III$. Cysteine | $R$. Addition of the compound to a saturated solution of $NaHCO_3$ results in effervescence. |
| $IV$. Caprolactam | $S$. The compound reacts with bromine water to give a white precipitate. |
| $T$. Treating the compound with neutral $FeCl_3$ solution produces violet color. |
Match column $-I$ and column $-II$ with the correct relation:
Column $-I$ Column $-II$ $(i).$ Prussian blue $(a).$ Presence of phosphorus $(ii).$ Yellow precipitate $(b).$ Presence of sulphur $(iii).$ Purple solution $(c).$ Presence of nitrogen $(iv).$ Black precipitate $(d).$ Presence of chlorine
| Column $-I$ | Column $-II$ |
|---|---|
| $(i).$ Prussian blue | $(a).$ Presence of phosphorus |
| $(ii).$ Yellow precipitate | $(b).$ Presence of sulphur |
| $(iii).$ Purple solution | $(c).$ Presence of nitrogen |
| $(iv).$ Black precipitate | $(d).$ Presence of chlorine |
Easy
View SolutionLassaigne's test for nitrogen is negative for which compound?
Easy
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