In which of the following compounds does the | vedclass

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(D) To determine the hybridization of the $C$ atom,we count the number of sigma bonds and lone pairs attached to it.$1$. In $HCOOH$ (formic acid),the

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$CH_3CHO$

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(D) To determine the hybridization of the $C$ atom,we count the number of sigma bonds and lone pairs attached to it.$1$. In $HCOOH$ (formic acid),the $C$ atom is bonded to $H$,$OH$,and double-bonded to $O$. It is $sp^2$ hybridized.$2$. In $(H_2N)_2CO$ (urea),the $C$ atom is bonded to two $NH_2$ groups and double-bonded to $O$. It is $sp^2$ hybridized.$3$. In $HCHO$ (formaldehyde),the $C$ atom is bonded to two $H$ atoms and double-bonded to $O$. It is $sp^2$ hybridized.$4$. In $CH_3CHO$ (acetaldehyde),the methyl carbon $(CH_3)$ is bonded to three $H$ atoms and one $C$ atom. Since it has four sigma bonds,it is $sp^3$ hybridized.

List-$I$	List-$II$
$(a)$ $SF_6$	$(i)$ $sp^3d^2$
$(b)$ $PCl_5$	(ii) $sp^3d$
$(c)$ $XeF_4$	(iii) $sp^3d^3$
$(d)$ $IF_7$	(iv) $sp^3d^2$

In which of the following compounds does the $C$ atom use $sp^3$ hybrid orbitals for bonding?

Similar Questions

Match the following:
List-$I$ List-$II$
$(a)$ $SF_6$ $(i)$ $sp^3d^2$
$(b)$ $PCl_5$ (ii) $sp^3d$
$(c)$ $XeF_4$ (iii) $sp^3d^3$
$(d)$ $IF_7$ (iv) $sp^3d^2$

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The type of hybrid orbitals used by the chlorine atom in $ClO_2^-$ is:

Which of the following has $sp^3$ hybridization?

$A$ $sp^3$ hybridized orbital contains

The hybridization of nitrogen atoms in $NO^{+}_2$,$NO^{-}_3$,and $NH^{+}_4$ respectively is:

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