The electronegativity values of F, Cl, Br, an | vedclass

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(A) The ionic character of a bond is directly proportional to the difference in electronegativity between the bonded atoms.Electronegativity of $H$ is

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$HF$

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(A) The ionic character of a bond is directly proportional to the difference in electronegativity between the bonded atoms.Electronegativity of $H$ is $2.1$.The electronegativity differences are:$HF: |4.0 - 2.1| = 1.9$$HCl: |3.0 - 2.1| = 0.9$$HBr: |2.8 - 2.1| = 0.7$$HI: |2.5 - 2.1| = 0.4$Since $HF$ has the largest electronegativity difference,it possesses the highest percentage of ionic character.

The electronegativity values of $F, Cl, Br,$ and $I$ are $4.0, 3.0, 2.8,$ and $2.5$ respectively. Which hydrogen halide has the highest percentage of ionic character?

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