If $\Lambda^{0}_{NaOAc} = 91 \, S \, cm^{2} \, mol^{-1}$ and $\Lambda^{0}_{HCl} = 496.2 \, S \, cm^{2} \, mol^{-1}$,what additional value is required to calculate $\Lambda^{0}_{HOAc}$?
- A$\Lambda^{0}_{H^{+}}$
- B$\Lambda^{0}_{CH_{3}COOH}$
- C$\Lambda^{0}_{NaCl}$
- D$\Lambda^{0}_{ClCH_{3}COOH}$
Explore More
Similar Questions
The specific conductance of $0.05 \ M$ $NaOH$ solution is $0.0115 \ S \ cm^{-1}$. What is its molar conductance $(\Lambda_{m})$ in $S \ cm^2 \ mol^{-1}$?
The molar conductivity of a $0.5 \ mol/dm^3$ solution of $AgNO_3$ with electrolytic conductivity of $5.76 \times 10^{-3} \ S \ cm^{-1}$ at $298 \ K$ is ......... $S \ cm^2/mol$.
MediumNEET 2016
View SolutionThe conductivity of a centimolar solution of $KCl$ at $25^{\circ} C$ is $0.0210 \, \Omega^{-1} cm^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} C$ is $60 \, \Omega$. The value of the cell constant is $......... \, cm^{-1}$.
DifficultNEET 2023
View SolutionIf the conductivity of a $0.5 \ M \ KCl$ solution at $298 \ K$ is $0.024 \ S \ cm^{-1}$,then the molar conductivity of the solution would be $S \ cm^2 \ mol^{-1}$.
Specific conductance of $0.2 \ M$ electrolyte solution at $20 \ ^oC$ temperature is $2.48 \times 10^{-4} \ ohm^{-1} \ cm^{-1}$. The molar conductance of the solution will be ............ $ohm^{-1} \ cm^2 \ mol^{-1}$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo