Which of the following is the correct increasing order of electronegativity for the given elements?
- A$C < N < Si < P$
- B$Si < P < C < N$
- C$N < C < P < Si$
- D$C < Si < N < P$
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Similar Questions
The outermost electronic configuration of the most electronegative element is
Easy
View SolutionIf the difference in electronegativities of two elements is very large,then
Medium
View SolutionAmong the following,the pairs of elements having approximately the same electronegativity values are:
$I$. $H$ and $P$
$II$. $Be$ and $Al$
$III$. $N$ and $Cl$
$IV$. $C$ and $P$
$I$. $H$ and $P$
$II$. $Be$ and $Al$
$III$. $N$ and $Cl$
$IV$. $C$ and $P$
Which of the following elements has the highest electronegativity?
Assertion : $F$ is more electronegative than $Cl$.
Reason : $F$ has higher electron affinity than $Cl$.
Reason : $F$ has higher electron affinity than $Cl$.
MediumAIIMS 2007
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