Match the following List-$I$ and List-$II$ and select the correct answer using the codes given below.
List-$I$ (Successive Ionization Enthalpy) $\left( kJ \, mol^{-1} \right)$ List-$II$
Element $IE_1$ $IE_2$ $IE_3$ Code Element $1$ $2080$ $3963$ $6130$ $(a)$ $H$ $2$ $520$ $7297$ $11810$ $(b)$ $Li$ $3$ $900$ $1758$ $14810$ $(c)$ $Be$ $4$ $800$ $2428$ $3660$ $(d)$ $B$ - - - - $(e)$ $Ne$
List-$I$ (Successive Ionization Enthalpy) $\left( kJ \, mol^{-1} \right)$ List-$II$
| Element | $IE_1$ | $IE_2$ | $IE_3$ | Code | Element |
| $1$ | $2080$ | $3963$ | $6130$ | $(a)$ | $H$ |
| $2$ | $520$ | $7297$ | $11810$ | $(b)$ | $Li$ |
| $3$ | $900$ | $1758$ | $14810$ | $(c)$ | $Be$ |
| $4$ | $800$ | $2428$ | $3660$ | $(d)$ | $B$ |
| - | - | - | - | $(e)$ | $Ne$ |
- A$1-(e), 2-(b), 3-(c), 4-(d)$
- B$1-(a), 2-(e), 3-(b), 4-(d)$
- C$1-(d), 2-(a), 3-(b), 4-(d)$
- D$1-(e), 2-(b), 3-(c), 4-(a)$
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View SolutionMatch List-$I$ with List-$II$ with correct code:
List-$I$ ($IE_1, IE_2, IE_3$ in $kJ \ mol^{-1}$) List-$II$ (Element) $A$. $1510$ $1$. $H$ $B$. $495, 6500, 10200$ $2$. $Li$ $C$. $840, 1630, 13100$ $3$. $Be$ $D$. $600, 2050, 3100$ $4$. $B$
| List-$I$ ($IE_1, IE_2, IE_3$ in $kJ \ mol^{-1}$) | List-$II$ (Element) |
|---|---|
| $A$. $1510$ | $1$. $H$ |
| $B$. $495, 6500, 10200$ | $2$. $Li$ |
| $C$. $840, 1630, 13100$ | $3$. $Be$ |
| $D$. $600, 2050, 3100$ | $4$. $B$ |
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