(D) The chemical formula for potassium dichromate is $K_2Cr_2O_7$. Let the oxidation state of $Cr$ be $x$. The sum of oxidation states of all atoms in

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(D) The chemical formula for potassium dichromate is $K_2Cr_2O_7$. Let the oxidation state of $Cr$ be $x$. The sum of oxidation states of all atoms in a neutral molecule is $0$. $2(K) + 2(Cr) + 7(O) = 0$ $2(+1) + 2(x) + 7(-2) = 0$ $2 + 2x - 14 = 0$ $2x - 12 = 0$ $2x = 12$ $x = +6$ Therefore,the oxidation state of $Cr$ is $6$.