The rate of diffusion of a gas is directly pr | vedclass

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(B) According to Graham's Law of diffusion,the rate of diffusion $r \propto \frac{1}{\sqrt{M}}$,where $M$ is the molar mass of the gas.From the ideal

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$\sqrt{\frac{P}{d}}$

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(B) According to Graham's Law of diffusion,the rate of diffusion $r \propto \frac{1}{\sqrt{M}}$,where $M$ is the molar mass of the gas.From the ideal gas equation,$PV = nRT = \frac{w}{M}RT$.Rearranging gives $PM = \frac{w}{V}RT = dRT$,where $d$ is the density.Thus,$M = \frac{dRT}{P}$.At a constant temperature,$M \propto \frac{d}{P}$.Substituting this into the rate equation: $r \propto \frac{1}{\sqrt{d/P}} = \sqrt{\frac{P}{d}}$.

The rate of diffusion of a gas is directly proportional to which of the following?

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