What is the relative rate of diffusion of a g | vedclass

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(A) According to Graham's Law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_1}{r

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$\frac{1}{7}$

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(A) According to Graham's Law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$.Given $M_{H_2} = 2 \ g/mol$ and $M_{gas} = 98 \ g/mol$.The relative rate of diffusion of the gas with respect to hydrogen is $\frac{r_{gas}}{r_{H_2}} = \sqrt{\frac{M_{H_2}}{M_{gas}}}$.Substituting the values: $\sqrt{\frac{2}{98}} = \sqrt{\frac{1}{49}} = \frac{1}{7}$.

What is the relative rate of diffusion of a gas (molecular weight = $98$) compared to hydrogen?

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