The density of ammonia gas at 27^{circ}C and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Using the ideal gas equation $PV = nRT$,where $n = \frac{m}{M}$.Density $d = \frac{m}{V} = \frac{PM}{RT}$.For ammonia $(NH_3)$,molar mass $M = 14

Vedclass · Accepted Answer

$2.07 \, g \, dm^{-3}$

Vedclass · Answer

(B) Using the ideal gas equation $PV = nRT$,where $n = \frac{m}{M}$.Density $d = \frac{m}{V} = \frac{PM}{RT}$.For ammonia $(NH_3)$,molar mass $M = 14 + 3(1) = 17 \, g \, mol^{-1}$.Given $P = 3 \, atm$,$T = 27 + 273 = 300 \, K$,and $R = 0.0821 \, L \, atm \, K^{-1} \, mol^{-1}$.$d = \frac{3 	imes 17}{0.0821 	imes 300} = \frac{51}{24.63} \approx 2.07 \, g \, L^{-1}$.Since $1 \, L = 1 \, dm^3$,the density is $2.07 \, g \, dm^{-3}$.

The density of ammonia gas at $27^{\circ}C$ and $3 \, atm$ pressure is approximately:

Similar Questions

State Charles' law in brief.

$16 \, g$ of oxygen and $3 \, g$ of hydrogen are mixed and kept at $760 \, mm$ pressure and $0 \, ^oC$. The total volume occupied by the mixture will be nearly

At what new pressure will $100 \ mL$ of a gas at a pressure of $720 \ mm$ occupy a volume of $84 \ mL$,keeping the temperature constant (in $mm$)?

What will be the volume in $L$ of $2.8 \ g$ of carbon monoxide at $27 \ ^oC$ temperature and $0.821 \ atm$ pressure? $(R = 0.0821 \ L \ atm \ mol^{-1} K^{-1})$

What will be the minimum pressure required to compress $500 \, dm^{3}$ of air at $1 \, bar$ to $200 \, dm^{3}$ at $30^{\circ} C$ (in $, bar$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module