The graph of V versus T for an ideal gas at c | vedclass

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(B) According to the ideal gas equation,$PV = nRT$,which can be rearranged as $V = (nR/P)T$.This represents a straight line equation $y = mx$,where th

Vedclass · Accepted Answer

$P_1 < P_2$

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(B) According to the ideal gas equation,$PV = nRT$,which can be rearranged as $V = (nR/P)T$.This represents a straight line equation $y = mx$,where the slope $m = nR/P$.Since the slope is inversely proportional to pressure $(m \propto 1/P)$,a smaller slope corresponds to a higher pressure.In the given graph,the slope of the line for $P_2$ is smaller than the slope of the line for $P_1$.Therefore,$P_2 > P_1$ or $P_1 < P_2$.

The graph of $V$ versus $T$ for an ideal gas at constant pressures $P_1$ and $P_2$ is shown below. Which of the following is correct?

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