An accelerated electron produces ...

$A$ parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is

$A$ parallel plate capacitor of capacitance $20 \; \mu F$ is being charged by a voltage source whose potential is changing at the rate of $3 \; V/s$. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively:

Electromagnetic waves are produced by

Write the Ampere-Maxwell law in the form of an equation.

Show that the magnetic field $B$ at a point in between the plates of a parallel-plate capacitor during charging is $B = \frac{{\mu _0 \epsilon _0 r}}{2} \cdot \frac{{dE}}{{dt}}$ (symbols have their usual meanings).