The work function of a metal is 2.51 eV. Wha | vedclass

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Question

(D) The work function $W_0$ is related to the threshold frequency $
u_0$ by the equation: $W_0 = h
u_0$.Here,$W_0 = 2.51 \ eV = 2.51 	imes 1.6 	im

Vedclass · Accepted Answer

$6.08 	imes 10^{14} \ Hz$

Vedclass · Answer

(D) The work function $W_0$ is related to the threshold frequency $
u_0$ by the equation: $W_0 = h
u_0$.Here,$W_0 = 2.51 \ eV = 2.51 	imes 1.6 	imes 10^{-19} \ J$.Planck's constant $h = 6.63 	imes 10^{-34} \ J \cdot s$.Substituting the values: $
u_0 = \frac{W_0}{h} = \frac{2.51 	imes 1.6 	imes 10^{-19}}{6.63 	imes 10^{-34}}$.$
u_0 \approx 0.6057 	imes 10^{15} \ Hz = 6.057 	imes 10^{14} \ Hz$.Rounding to the nearest provided option,we get $6.08 	imes 10^{14} \ Hz$ (using $h \approx 6.6 	imes 10^{-34} \ J \cdot s$ as per the provided solution logic).

The work function of a metal is $2.51 \ eV$. What is its threshold frequency?

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