The electron transition required for the emission of characteristic $K_\beta$ $X$-rays is:

  • A
    $n = 2$ to $n = 1$
  • B
    $n = 3$ to $n = 2$
  • C
    $n = 3$ to $n = 1$
  • D
    $n = 4$ to $n = 2$

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The energy of a photon of light with wavelength $5000\,\mathring{A}$ is approximately $2.5\,\text{eV}$. In this way,the energy of an $X$-ray photon with wavelength $1\,\mathring{A}$ would be:

If the wavelength of the $K_\alpha$ line of an element with atomic number $43$ is $\lambda$,then the wavelength of the $K_\alpha$ line of an element with atomic number $29$ is:

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The emission of continuous $X$-rays is due to:

Frequency of the $K_{\alpha}$ $X$-ray for the element calcium $(Ca, Z = 20)$ is $8.95 \times 10^{17} \ Hz$. The frequency of the $K_{\alpha}$ $X$-ray for the element cadmium $(Cd, Z = 48)$ will be:

For the production of characteristic $K_{\beta}$ $X$-rays,the electron transition is:

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