(B) The energy $E$ and momentum $p$ of a photon are related to its wavelength $\lambda$ by the following equations:$E = \frac{hc}{\lambda}$$p = \frac{

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Both $p$ and $E$ will increase.

(B) The energy $E$ and momentum $p$ of a photon are related to its wavelength $\lambda$ by the following equations:$E = \frac{hc}{\lambda}$$p = \frac{h}{\lambda}$Where $h$ is Planck's constant and $c$ is the speed of light.Since both $E$ and $p$ are inversely proportional to the wavelength $\lambda$ ($E \propto \frac{1}{\lambda}$ and $p \propto \frac{1}{\lambda}$),if the wavelength $\lambda$ is decreased,both the energy $E$ and the momentum $p$ will increase.

Class 12 Physics Dual Nature of Radiation and matter Particle Nature of Light : Photon

Easy

If $E$ and $p$ are the energy and momentum of a photon respectively,what happens if the wavelength of the photon is decreased?

A
Both $p$ and $E$ will decrease.
B
Both $p$ and $E$ will increase.
C
$p$ will increase and $E$ will decrease.
D
$p$ will decrease and $E$ will increase.

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Class 12 Questions

Class 12

Physics Questions

Chapter

Dual Nature of Radiation and matter

Subtopic

Particle Nature of Light : Photon

An important spectral emission line has a wavelength of $21 \ cm$. The corresponding photon energy is $(h = 6.62 \times 10^{-34} \ J \cdot s; \ c = 3 \times 10^8 \ m/s)$.

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The ratio of energies of photons with wavelengths $\lambda_1 = 150 \ nm$ and $\lambda_2 = 300 \ nm$ is:

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Find the number of photons emitted per second by a $100 \ W$ bulb emitting light of wavelength $540 \ nm$. (Given: $h = 6 \times 10^{-34} \ J \cdot s$)

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$A$ photon creates an electron-positron pair with equal kinetic energy. If the kinetic energy of each particle is $0.29 \ MeV$,the energy of the photon must be .......... $MeV$.

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$A$ gamma ray photon creates an electron-positron pair. If the rest mass energy of an electron is $0.5\, MeV$ and the total kinetic energy $(K.E.)$ of the electron-positron pair is $0.78\, MeV$,then the energy of the gamma ray photon must be.......$MeV$.

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If $E$ and $p$ are the energy and momentum of a photon respectively,what happens if the wavelength of the photon is decreased?

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An important spectral emission line has a wavelength of $21 \ cm$. The corresponding photon energy is $(h = 6.62 \times 10^{-34} \ J \cdot s; \ c = 3 \times 10^8 \ m/s)$.

The ratio of energies of photons with wavelengths $\lambda_1 = 150 \ nm$ and $\lambda_2 = 300 \ nm$ is:

Find the number of photons emitted per second by a $100 \ W$ bulb emitting light of wavelength $540 \ nm$. (Given: $h = 6 \times 10^{-34} \ J \cdot s$)

$A$ photon creates an electron-positron pair with equal kinetic energy. If the kinetic energy of each particle is $0.29 \ MeV$,the energy of the photon must be .......... $MeV$.

$A$ gamma ray photon creates an electron-positron pair. If the rest mass energy of an electron is $0.5\, MeV$ and the total kinetic energy $(K.E.)$ of the electron-positron pair is $0.78\, MeV$,then the energy of the gamma ray photon must be.......$MeV$.

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