When light is incident on a surface,photoelec | vedclass

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy of emitted photoelectrons is given by $K_{max} = h
u - \phi$,where $h

Vedclass · Accepted Answer

The kinetic energy is less than or equal to the maximum kinetic energy.

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy of emitted photoelectrons is given by $K_{max} = h
u - \phi$,where $h
u$ is the energy of the incident photon and $\phi$ is the work function of the metal.Since some electrons lose energy due to collisions before escaping the surface,the actual kinetic energy $K$ of the emitted photoelectrons ranges from $0$ to $K_{max}$.Therefore,the kinetic energy of any emitted photoelectron is always less than or equal to the maximum kinetic energy $(K \le K_{max})$.

When light is incident on a surface,photoelectrons are emitted. For these photoelectrons,which of the following is true?

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