The wavelength of an X-ray photon is 0.01 ma | vedclass

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(A) The wavelength of the photon is given by $\lambda = 0.01 \ \mathring A = 0.01 	imes 10^{-10} \ m = 10^{-12} \ m$. The momentum $p$ of a photon is

Vedclass · Accepted Answer

$6.6 	imes 10^{-22}$

Vedclass · Answer

(A) The wavelength of the photon is given by $\lambda = 0.01 \ \mathring A = 0.01 	imes 10^{-10} \ m = 10^{-12} \ m$. The momentum $p$ of a photon is related to its wavelength $\lambda$ by the de Broglie relation: $p = \frac{h}{\lambda}$. Substituting the values,where Planck's constant $h = 6.63 	imes 10^{-34} \ J \ s$ (approximated as $6.6 	imes 10^{-34} \ J \ s$ for this calculation): $p = \frac{6.6 	imes 10^{-34}}{10^{-12}} = 6.6 	imes 10^{-22} \ kg \ m/s$.

The wavelength of an $X$-ray photon is $0.01 \ \mathring A$. Its momentum in $kg \ m/s$ is .........

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