What is the momentum of a photon with a frequ | vedclass

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(C) The momentum $p$ of a photon is given by the formula $p = \frac{h}{\lambda}$.Since the speed of light $c = 
u \lambda$,we have $\lambda = \frac{c

Vedclass · Accepted Answer

$2.2 	imes 10^{-33} \ kg \ m/s$

Vedclass · Answer

(C) The momentum $p$ of a photon is given by the formula $p = \frac{h}{\lambda}$.Since the speed of light $c = 
u \lambda$,we have $\lambda = \frac{c}{
u}$.Substituting this into the momentum formula,we get $p = \frac{h
u}{c}$.Given values are frequency $
u = 10^9 \ Hz$,Planck's constant $h = 6.6 	imes 10^{-34} \ J \cdot s$,and speed of light $c = 3 	imes 10^8 \ m/s$.$p = \frac{(6.6 	imes 10^{-34} \ J \cdot s) 	imes (10^9 \ Hz)}{3 	imes 10^8 \ m/s}$.$p = \frac{6.6}{3} 	imes 10^{-34 + 9 - 8} \ kg \ m/s$.$p = 2.2 	imes 10^{-33} \ kg \ m/s$.

What is the momentum of a photon with a frequency of $10^9 \ Hz$?

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