(C) We know that $1 \, m \approx 3.28084 \, ft$.To convert the acceleration due to gravity from $m/s^2$ to $ft/s^2$,we multiply the value by the conve

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(C) We know that $1 \, m \approx 3.28084 \, ft$.To convert the acceleration due to gravity from $m/s^2$ to $ft/s^2$,we multiply the value by the conversion factor:$g = 9.8 \, m/s^2 \times 3.28084 \, ft/m$$g \approx 32.14 \, ft/s^2$.Rounding to the nearest whole number,we get $g \approx 32 \, ft/s^2$.

Class 11 Physics Units, Dimensions and Measurement Units

Easy

The value of acceleration due to gravity is $9.8 \, m s^{-2}$. Its value in $ft/s^2$ is approximately:

A
$23$
B
$29$
C
$32$
D
$38$

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Units, Dimensions and Measurement

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Units

What is the $SI$ unit of density?

EasyMHT CET 2021

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Why can $10^6 \, km$ not be represented as $M \, km$?

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Match List-$I$ with List-$II$ and select the correct answer by using the codes given below the lists.

List-$I$ List-$II$

$(A)$ Distance between earth and stars $(1)$ Microns

$(B)$ Inter-atomic distance in a solid $(2)$ $\mathring{A}$s

$(C)$ Size of the nucleus $(3)$ Light years

$(D)$ Wavelength of infrared laser $(4)$ Fermi

List-$I$	List-$II$
$(A)$ Distance between earth and stars	$(1)$ Microns
$(B)$ Inter-atomic distance in a solid	$(2)$ $\mathring{A}$s
$(C)$ Size of the nucleus	$(3)$ Light years
$(D)$ Wavelength of infrared laser	$(4)$ Fermi