Find the variance of 2, 4, 6, 8, 10. | vedclass

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(A) The mean $(\overline{x})$ is calculated as $\overline{x} = \frac{\sum x_i}{n}$.$\overline{x} = \frac{2+4+6+8+10}{5} = \frac{30}{5} = 6$.The varian

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$8$

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(A) The mean $(\overline{x})$ is calculated as $\overline{x} = \frac{\sum x_i}{n}$.$\overline{x} = \frac{2+4+6+8+10}{5} = \frac{30}{5} = 6$.The variance $(\sigma^2)$ is calculated as $\sigma^2 = \frac{\sum (x_i - \overline{x})^2}{n}$.$\sigma^2 = \frac{(2-6)^2 + (4-6)^2 + (6-6)^2 + (8-6)^2 + (10-6)^2}{5}$.$\sigma^2 = \frac{(-4)^2 + (-2)^2 + 0^2 + 2^2 + 4^2}{5}$.$\sigma^2 = \frac{16 + 4 + 0 + 4 + 16}{5} = \frac{40}{5} = 8$.

Find the variance of $2, 4, 6, 8, 10$.

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