Statement-I: If a leap year is selected at ra | vedclass

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(A) leap year consists of $366$ days.$366$ days = $52$ weeks and $2$ extra days.These $2$ extra days can be: (Sunday,Monday),(Monday,Tuesday),(Tuesday

Vedclass · Accepted Answer

Statement-$I$ is true. Statement-$II$ is true. Statement-$II$ is the correct explanation for Statement-$I$.

Vedclass · Answer

(A) leap year consists of $366$ days.$366$ days = $52$ weeks and $2$ extra days.These $2$ extra days can be: (Sunday,Monday),(Monday,Tuesday),(Tuesday,Wednesday),(Wednesday,Thursday),(Thursday,Friday),(Friday,Saturday),or (Saturday,Sunday).There are $7$ possible outcomes for these $2$ days.For the year to have $53$ Sundays,one of the $2$ extra days must be a Sunday.This occurs in $2$ cases: (Saturday,Sunday) and (Sunday,Monday).Therefore,the probability is $2/7$.Since Statement-$II$ provides the basis for calculating the extra days in a leap year,it is the correct explanation for Statement-$I$.

Statement-$I$: If a leap year is selected at random,the probability of it having $53$ Sundays is $2/7$.
Statement-$II$: $A$ leap year has $366$ days.

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Statement-$I$: If a leap year is selected at random,the probability of it having $53$ Sundays is $2/7$.Statement-$II$: $A$ leap year has $366$ days.