A box contains 5 blue and 4 white chalks. If | vedclass

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(D) Total number of chalks = $5 + 4 = 9$. Total ways to select $2$ chalks from $9$ is $n(S) = _9C_2 = \frac{9 	imes 8}{2 	imes 1} = 36$. Let $A$ be

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$4/9$

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(D) Total number of chalks = $5 + 4 = 9$. Total ways to select $2$ chalks from $9$ is $n(S) = _9C_2 = \frac{9 	imes 8}{2 	imes 1} = 36$. Let $A$ be the event that both chalks are white. The number of ways to select $2$ white chalks from $4$ is $n(A) = _4C_2 = \frac{4 	imes 3}{2 	imes 1} = 6$. Let $B$ be the event that both chalks are blue. The number of ways to select $2$ blue chalks from $5$ is $n(B) = _5C_2 = \frac{5 	imes 4}{2 	imes 1} = 10$. Since $A$ and $B$ are mutually exclusive events,the probability that both chalks are of the same color is $P(A \cup B) = P(A) + P(B)$. $P(A) = \frac{6}{36} = \frac{1}{6}$. $P(B) = \frac{10}{36} = \frac{5}{18}$. $P(A \cup B) = \frac{6}{36} + \frac{10}{36} = \frac{16}{36} = \frac{4}{9}$.

$A$ box contains $5$ blue and $4$ white chalks. If two chalks are chosen at random,what is the probability that both chalks are of the same color?

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