(B) For a quadratic equation $ax^2 + bx + c = 0$ to have equal roots,the discriminant $D$ must be equal to $0$.The discriminant $D = b^2 - 4ac$.Given

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(B) For a quadratic equation $ax^2 + bx + c = 0$ to have equal roots,the discriminant $D$ must be equal to $0$.The discriminant $D = b^2 - 4ac$.Given the equation $x^2 + px + 64 = 0$,we have $a = 1$,$b = p$,and $c = 64$.Setting $D = 0$:$p^2 - 4(1)(64) = 0$$p^2 - 256 = 0$$p^2 = 256$$p = \pm 16$.Since it is given that $p > 0$,we take $p = 16$.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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For what value of $p > 0$ do the roots of the equation $x^2 + px + 64 = 0$ become equal?

A
$8$
B
$16$
C
$32$
D
$64$

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4-2.Quadratic Equations and Inequations

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Solution of quadratic equations and Nature of roots

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For what value of $p > 0$ do the roots of the equation $x^2 + px + 64 = 0$ become equal?

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