Out of 10 points in a plane,6 are collinear. | vedclass

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(A) The total number of ways to select $3$ points out of $10$ is given by $\binom{10}{3} = \frac{10 	imes 9 	imes 8}{3 	imes 2 	imes 1} = 120$. Si

Vedclass · Accepted Answer

$100$

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(A) The total number of ways to select $3$ points out of $10$ is given by $\binom{10}{3} = \frac{10 	imes 9 	imes 8}{3 	imes 2 	imes 1} = 120$. Since $6$ points are collinear,they cannot form a triangle. The number of ways to select $3$ points from these $6$ collinear points is $\binom{6}{3} = \frac{6 	imes 5 	imes 4}{3 	imes 2 	imes 1} = 20$. Therefore,the number of triangles that can be formed is $120 - 20 = 100$.

Out of $10$ points in a plane,$6$ are collinear. How many triangles can be formed by joining these points?

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