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(C) Given: Distance between slits $d = 0.12 \, mm = 0.012 \, cm = 1.2 	imes 10^{-4} \, m$.Distance of screen $D = 1 \, m = 100 \, cm$.Wavelength $\la

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(C) Given: Distance between slits $d = 0.12 \, mm = 0.012 \, cm = 1.2 	imes 10^{-4} \, m$.Distance of screen $D = 1 \, m = 100 \, cm$.Wavelength $\lambda = 6000 \, \mathring{A} = 6000 	imes 10^{-10} \, m = 6 	imes 10^{-7} \, m$.The position of the $n^{th}$ bright fringe is given by $x_n = \frac{n D \lambda}{d}$.For the $3^{rd}$ bright fringe,$n = 3$.$x_3 = \frac{3 	imes 1 	imes 6 	imes 10^{-7}}{1.2 	imes 10^{-4}}$.$x_3 = \frac{18 	imes 10^{-7}}{1.2 	imes 10^{-4}} = 15 	imes 10^{-3} \, m$.$x_3 = 1.5 	imes 10^{-2} \, m = 1.5 \, cm$.

In Young's double-slit experiment,the slits are separated by $0.12 \, mm$ and the screen is at a distance of $1 \, m$. Find the distance of the $3^{rd}$ bright fringe from the center of the screen in $cm$. Given $\lambda = 6000 \, \mathring{A}$.

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