Initially,parallel cylindrical wavefronts tra | vedclass

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(C) The refractive index is given by $\mu(I) = \mu_0 + \mu_2 I$. Since the intensity $I$ is maximum at the axis and decreases as we move away from the

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It converges.

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(C) The refractive index is given by $\mu(I) = \mu_0 + \mu_2 I$. Since the intensity $I$ is maximum at the axis and decreases as we move away from the axis (as shown by $x$ in the figure),the refractive index $\mu$ is also maximum at the axis and decreases as we move away from it.Since the speed of light $v = c/\mu$,the speed is minimum at the axis and increases as we move away from the axis.Consequently,the part of the wavefront near the axis travels slower than the parts further away from the axis.This causes the wavefront to bend and converge towards the axis,resulting in a convex shape as shown in the figure.

Initially,parallel cylindrical wavefronts travel in a medium with a refractive index $\mu(I) = \mu_0 + \mu_2 I$,where $\mu_0$ and $\mu_2$ are positive constants and $I$ is the intensity. The intensity decreases as the radius increases. What happens when it enters the second medium?

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