State two conditions for obtaining sustained | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Conditions for sustained interference of light: $(i)$ The sources must be coherent. $(ii)$ The sources must be monochromatic.The fringe width is g

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) Conditions for sustained interference of light: $(i)$ The sources must be coherent. $(ii)$ The sources must be monochromatic.The fringe width is given by $\beta = \frac{\lambda D}{d}$.For the first case: $\beta_1 = \frac{\lambda_1 D_1}{d_1}$,where $\lambda_1 = 400 \, nm$.For the second case: $\beta_2 = \frac{\lambda_2 D_2}{d_2}$,where $\lambda_2 = 600 \, nm$ and $d_2 = \frac{d_1}{2}$.Given that the fringe width remains the same,$\beta_1 = \beta_2$:$\frac{\lambda_1 D_1}{d_1} = \frac{\lambda_2 D_2}{d_2}$$\frac{D_1}{D_2} = \frac{\lambda_2 d_1}{\lambda_1 d_2} = \frac{600}{400} 	imes \frac{d_1}{d_1/2} = \frac{3}{2} 	imes 2 = 3$.Thus,the ratio of the distances is $3:1$.

Similar Questions

Four monochromatic and coherent sources of light,emitting waves in phase of wavelength $\lambda$,are placed at the points $x = 0, d, 2d$,and $3d$ on the $x$-axis. Then:

In Young's double slit experiment,the width of fringes can be increased if we decrease the

In a Young's double slit experiment,the intensity at a point where the path difference is $\frac{\lambda}{6}$ ($\lambda$ being the wavelength of the light used) is $I$. If $I_0$ denotes the maximum intensity,$I/I_0$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module