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(C) The fringe width $\beta$ in Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$.Given values are:Wavelength $\la

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$0.5$

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(C) The fringe width $\beta$ in Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$.Given values are:Wavelength $\lambda = 550 \,nm = 550 	imes 10^{-9} \,m$.Distance between slits $d = 1.10 \,mm = 1.10 	imes 10^{-3} \,m$.Distance between screen and slits $D = 1 \,m$.Substituting these values into the formula:$\beta = \frac{550 	imes 10^{-9} 	imes 1}{1.10 	imes 10^{-3}}$$\beta = \frac{550}{1.10} 	imes 10^{-6} \,m$$\beta = 500 	imes 10^{-6} \,m = 0.5 	imes 10^{-3} \,m$.Since $10^{-3} \,m = 1 \,mm$,we get $\beta = 0.5 \,mm$.

Young's double-slit experiment is performed with a wavelength of $550 \,nm$. If the distance between the two slits is $1.10 \,mm$ and the distance between the screen and the slits is $1 \,m$,then the distance between two consecutive bright or dark fringes is .....$mm$.

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