(B) The shift in the interference pattern $(\Delta y)$ is given by the formula:$\Delta y = \frac{D}{d} t(\mu - 1)$Given values:$D = 100 \, cm = 1 \, m

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(B) The shift in the interference pattern $(\Delta y)$ is given by the formula:$\Delta y = \frac{D}{d} t(\mu - 1)$Given values:$D = 100 \, cm = 1 \, m$$d = 0.5 \, mm = 0.5 \times 10^{-3} \, m$$t = 2.5 \times 10^{-5} \, m$$\mu = 1.5$Substituting the values:$\Delta y = \frac{1}{0.5 \times 10^{-3}} \times (2.5 \times 10^{-5}) \times (1.5 - 1)$$\Delta y = \frac{2.5 \times 10^{-5} \times 0.5}{0.5 \times 10^{-3}}$$\Delta y = 2.5 \times 10^{-2} \, m$Converting to $cm$:$\Delta y = 2.5 \times 10^{-2} \times 100 \, cm = 2.5 \, cm$.

Class 12 Physics Wave Optics Variations in YDSE (Young's Double Slit Experiment)

Medium

$A$ transparent medium of refractive index $\mu = 1.5$ and thickness $t = 2.5 \times 10^{-5} \, m$ is placed in front of one of the slits in a Young's double-slit experiment. By what distance (in $cm$) will the interference pattern shift? The distance between the two slits is $d = 0.5 \, mm$ and the distance between the screen and the slits is $D = 100 \, cm$.

A
$5$
B
$2.5$
C
$0.25$
D
$0.1$

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Variations in YDSE (Young's Double Slit Experiment)

In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then in the interference pattern

MediumIIT 2000

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To make the central fringe at the centre $O$,a mica sheet of refractive index $1.5$ is introduced. Choose the correct statement$(s)$.

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In $YDSE$,the source $S$ placed symmetrically with respect to the slits $S_1$ and $S_2$ is now moved parallel to the plane of the slits so that it is closer to the upper slit $S_1$,as shown. Then,

Medium

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$A$ thin mica sheet of thickness $2 \times 10^{-6} \ m$ and refractive index $\mu = 1.5$ is introduced in the path of the first wave. The wavelength of the wave used is $5000 \ \mathring{A}$. The central bright maximum will shift:

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If a thin mica sheet of thickness $t$ and refractive index $\mu = 5/3$ is placed in the path of one of the interfering beams as shown in the figure,then the displacement of the fringe system is:

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In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then in the interference pattern

To make the central fringe at the centre $O$,a mica sheet of refractive index $1.5$ is introduced. Choose the correct statement$(s)$.

In $YDSE$,the source $S$ placed symmetrically with respect to the slits $S_1$ and $S_2$ is now moved parallel to the plane of the slits so that it is closer to the upper slit $S_1$,as shown. Then,

$A$ thin mica sheet of thickness $2 \times 10^{-6} \ m$ and refractive index $\mu = 1.5$ is introduced in the path of the first wave. The wavelength of the wave used is $5000 \ \mathring{A}$. The central bright maximum will shift:

If a thin mica sheet of thickness $t$ and refractive index $\mu = 5/3$ is placed in the path of one of the interfering beams as shown in the figure,then the displacement of the fringe system is:

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