A voltmeter of resistance 998 Omega is connec | vedclass

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(C) The $emf$ of the cell is $E = 2\ V$ and its internal resistance is $r = 2\ \Omega$.The voltmeter has a resistance $R = 998\ \Omega$.When the voltm

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$4 	imes 10^{-3}\ V$

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(C) The $emf$ of the cell is $E = 2\ V$ and its internal resistance is $r = 2\ \Omega$.The voltmeter has a resistance $R = 998\ \Omega$.When the voltmeter is connected across the cell,the current $I$ flowing through the circuit is given by $I = \frac{E}{R + r}$.Substituting the values,$I = \frac{2}{998 + 2} = \frac{2}{1000} = 2 	imes 10^{-3}\ A$.The voltmeter measures the terminal voltage $V = E - Ir$.The error in measurement is the difference between the actual $emf$ and the measured terminal voltage,which is equal to the voltage drop across the internal resistance: $	ext{Error} = Ir$.$	ext{Error} = (2 	imes 10^{-3}\ A) 	imes (2\ \Omega) = 4 	imes 10^{-3}\ V$.

$A$ voltmeter of resistance $998\ \Omega$ is connected to a cell of $emf$ $2\ V$ and internal resistance $2\ \Omega$. The error in the measurement of $emf$ will be:

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