(C) Given: Current $I = 1.344 \, A$,Area $A = 1 \, mm^2 = 1 \times 10^{-6} \, m^2$,and electron density $n = 8.4 \times 10^{22} \, cm^{-3} = 8.4 \time

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(C) Given: Current $I = 1.344 \, A$,Area $A = 1 \, mm^2 = 1 \times 10^{-6} \, m^2$,and electron density $n = 8.4 \times 10^{22} \, cm^{-3} = 8.4 \times 10^{28} \, m^{-3}$.The formula for drift velocity is $v_d = \frac{I}{neA}$.Substituting the values:$v_d = \frac{1.344}{(8.4 \times 10^{28}) \times (1.6 \times 10^{-19}) \times (1 \times 10^{-6})}$$v_d = \frac{1.344}{8.4 \times 1.6 \times 10^{3}}$$v_d = \frac{1.344}{13.44 \times 10^{3}} = 0.1 \times 10^{-3} \, m/s = 0.1 \, mm/s$.

Class 12 Physics Current Electricity Current Density, Drift Velocity and Mobility

Medium

$A$ current of $1.344 \, A$ flows through a copper wire of cross-sectional area $1 \, mm^2$. If the number of free electrons per unit volume is $8.4 \times 10^{22} \, cm^{-3}$,then the drift velocity is:

A
$1.0 \, mm/s$
B
$1.0 \, m/s$
C
$0.1 \, mm/s$
D
$0.01 \, mm/s$

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Current Electricity

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Current Density, Drift Velocity and Mobility

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$A$ current of $1.344 \, A$ flows through a copper wire of cross-sectional area $1 \, mm^2$. If the number of free electrons per unit volume is $8.4 \times 10^{22} \, cm^{-3}$,then the drift velocity is:

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The drift velocity of the electrons in a copper wire of length $2\ m$ under the application of a potential difference of $200\ V$ is $0.5\ m/s$. Their mobility (in $m^2 V^{-1} s^{-1}$) is

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