A bullet of mass 2, g has a charge of 2, mu C | vedclass

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Question

(A) Given:Mass $m = 2\, g = 2 	imes 10^{-3}\, kg$Charge $q = 2\, \mu C = 2 	imes 10^{-6}\, C$Final velocity $v = 10\, m/s$Initial velocity $u = 0\,

Vedclass · Accepted Answer

$50\, kV$

Vedclass · Answer

(A) Given:Mass $m = 2\, g = 2 	imes 10^{-3}\, kg$Charge $q = 2\, \mu C = 2 	imes 10^{-6}\, C$Final velocity $v = 10\, m/s$Initial velocity $u = 0\, m/s$According to the work-energy theorem,the work done by the electric field is equal to the change in kinetic energy:$W = \Delta K$$qV = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$Since $u = 0$,the equation becomes:$qV = \frac{1}{2}mv^2$$V = \frac{mv^2}{2q}$Substituting the values:$V = \frac{(2 	imes 10^{-3}\, kg) 	imes (10\, m/s)^2}{2 	imes (2 	imes 10^{-6}\, C)}$$V = \frac{2 	imes 10^{-3} 	imes 100}{4 	imes 10^{-6}}$$V = \frac{0.2}{4 	imes 10^{-6}} = 0.05 	imes 10^6 = 50,000\, V$$V = 50\, kV$Therefore,the correct option is $A$.

$A$ bullet of mass $2\, g$ has a charge of $2\, \mu C$. Through what potential difference must it be accelerated,starting from rest,to acquire a speed of $10\, m/s$?

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