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(B) $1$. The current $I$ flowing through the conductor is constant throughout because it is a series circuit.$2$. Current density $J = I/A$. Since the

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The current density is lower at $P$ than at $Q$.

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(B) $1$. The current $I$ flowing through the conductor is constant throughout because it is a series circuit.$2$. Current density $J = I/A$. Since the cross-sectional area $A_P > A_Q$, the current density $J_P $3$. Electric field $E = J/\sigma = I/(A\sigma)$. Since $A_P > A_Q$, $E_P $4$. The rate of heat production per unit length is $dH/dx = I^2 R/dx = I^2 \rho / A$. Since $A_P > A_Q$, the rate of heat production is lower at $P$ than at $Q$.$5$. Therefore, the correct statement is that the current density is lower at $P$ than at $Q$ (Option $B$).

$A$ conductor of non-uniform cross-section is connected to a source of constant potential difference as shown in the figure. Then:

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