Three prisms $1, 2,$ and $3$ have a prism angle $A = 60^{\circ}$. Their refractive indices are $1.4, 1.5,$ and $1.6$ respectively. If $\delta_1, \delta_2,$ and $\delta_3$ are their angles of deviation,then:

  • A
    $\delta_3 > \delta_2 > \delta_1$
  • B
    $\delta_1 > \delta_2 > \delta_3$
  • C
    $\delta_1 = \delta_2 = \delta_3$
  • D
    $\delta_2 > \delta_1 > \delta_3$

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The refractive index of the material of a glass prism is $\sqrt{3}$. If the angle of minimum deviation is equal to the angle of the prism,then the angle of the prism is:
$\left(\cos 30^{\circ} = \frac{\sqrt{3}}{2} = \sin 60^{\circ}, \sin 30^{\circ} = \frac{1}{2} = \cos 60^{\circ}\right)$ (in $^{\circ}$)

$A$ given ray of light suffers minimum deviation in an equilateral prism $P$. Additional prisms $Q$ and $R$ of identical shape and material are now added to $P$ as shown in the figure. The ray will suffer

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