A person cannot see objects clearly beyond a | vedclass

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(B) The person is suffering from myopia (nearsightedness),as they cannot see distant objects clearly. The far point of the person is $v = -40 \, cm$.T

Vedclass · Accepted Answer

$-2.5 \, D$

Vedclass · Answer

(B) The person is suffering from myopia (nearsightedness),as they cannot see distant objects clearly. The far point of the person is $v = -40 \, cm$.To correct this,we need to use a concave lens that forms a virtual image of an object at infinity at the person's far point $(u = -\infty)$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{-40} - \frac{1}{-\infty} = \frac{1}{-40} - 0 = -\frac{1}{40} \, cm^{-1}$.The power of the lens $P$ is given by $P = \frac{100}{f}$ (where $f$ is in $cm$).$P = \frac{100}{-40} = -2.5 \, D$.

$A$ person cannot see objects clearly beyond a distance of $40 \, cm$. What power of lens should be prescribed for them?

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