The image formed by a convex mirror of focal | vedclass

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(C) For a convex mirror,the magnification $m$ is given by $m = \frac{f}{f - u}$,where $f$ is the focal length and $u$ is the object distance (which is

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$(n - 1) f$

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(C) For a convex mirror,the magnification $m$ is given by $m = \frac{f}{f - u}$,where $f$ is the focal length and $u$ is the object distance (which is negative).Given that the image size is $(1/n)$ times the object size,the magnification $m = +\frac{1}{n}$ (since the image is virtual and erect).Substituting the values: $\frac{1}{n} = \frac{f}{f - u}$.Rearranging the equation: $f - u = nf$.Solving for $u$: $u = f - nf = -(n - 1)f$.The distance of the object from the mirror is the magnitude of $u$,which is $|u| = (n - 1)f$.

The image formed by a convex mirror of focal length $f$ is $(1/n)$ times the size of the object. The distance of the object from the mirror is:

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