A point object is placed at a distance of 30 | vedclass

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(D) Given: Object distance $u = -30 \, cm$ (by sign convention).Focal length of convex mirror $f = +30 \, cm$.Using the mirror formula: $\frac{1}{f} =

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$15 \, cm$ behind the mirror

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(D) Given: Object distance $u = -30 \, cm$ (by sign convention).Focal length of convex mirror $f = +30 \, cm$.Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the values: $\frac{1}{30} = \frac{1}{v} + \frac{1}{-30}$.Rearranging the terms: $\frac{1}{v} = \frac{1}{30} + \frac{1}{30} = \frac{2}{30} = \frac{1}{15}$.Therefore,$v = +15 \, cm$.The positive sign indicates that the image is formed $15 \, cm$ behind the mirror.

$A$ point object is placed at a distance of $30 \, cm$ from a convex mirror of focal length $30 \, cm$. Where will the image be formed?

Similar Questions

$A$ convex mirror of focal length $10\,cm$ is shown in the figure. $A$ linear object $AB = 5\,cm$ is placed along the optical axis. Point $B$ is at a distance of $20\,cm$ from the pole of the mirror. Then,the size of the image of $AB$ will be:

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