For the given Common Emitter $(CE)$ transistor circuit,the base current is $I_B = 0.04 \text{ mA}$. If the current gain $\beta = 100$ and the collector-emitter voltage $V_{CE} = 12 \text{ V}$,find the value of the collector resistance $R_C$ in $\text{k}\Omega$.

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.

In a $PNP$ transistor,the base is the $N$-region. Its width relative to the $P$-region is

For a common emitter transistor,if $\frac{I_{C}}{I_{E}}=0.95$,then the current gain is

Consider an $NPN$ transistor amplifier in common-emitter configuration. The current gain of the transistor is $100$. If the collector current changes by $1\, mA$,what will be the change in emitter current in $mA$?

In an $NPN$ transistor circuit,the collector current is $10 \ mA$. If $95\%$ of the electrons emitted reach the collector,what is the base current in $mA$?