The resultant voltage gain in a series combin | vedclass

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(B) In the given figure,two amplifiers with voltage gains $A_{V1}$ and $A_{V2}$ are connected in series.For the first amplifier,the voltage gain is $A

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Equal to the product of the voltage gains of each amplifier

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(B) In the given figure,two amplifiers with voltage gains $A_{V1}$ and $A_{V2}$ are connected in series.For the first amplifier,the voltage gain is $A_{V1} = \frac{v_{o1}}{v_i}$.For the second amplifier,the voltage gain is $A_{V2} = \frac{v_o}{v_{o1}}$.When both amplifiers are connected in series,the combined voltage gain $A_V$ is given by:$A_V = \frac{v_o}{v_i} = \left( \frac{v_o}{v_{o1}} ight) 	imes \left( \frac{v_{o1}}{v_i} ight)$Therefore,$A_V = A_{V1} 	imes A_{V2}$.

The resultant voltage gain in a series combination of two or more amplifiers is .......

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