In the given transistor circuit,the base curr | vedclass

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(C) From the given circuit,applying Kirchhoff's voltage law to the base-emitter loop:$V_{source} = I_B R_b + V_{BE}$Given $V_{source} = 7 \ V$,$I_B =

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$200$

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(C) From the given circuit,applying Kirchhoff's voltage law to the base-emitter loop:$V_{source} = I_B R_b + V_{BE}$Given $V_{source} = 7 \ V$,$I_B = 35 \ \mu A = 35 	imes 10^{-6} \ A$,and $V_{BE} \approx 0 \ V$.Substituting the values:$7 = (35 	imes 10^{-6}) 	imes R_b + 0$$R_b = \frac{7}{35 	imes 10^{-6}} \ \Omega$$R_b = \frac{1}{5} 	imes 10^6 \ \Omega = 0.2 	imes 10^6 \ \Omega = 200 \ 	imes 10^3 \ \Omega = 200 \ k\Omega$.

In the given transistor circuit,the base current is $35 \ \mu A$. If the value of $V_{BE}$ is negligible,what is the value of $R_b$ in $k\Omega$?

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