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(D) The drift velocity is given by the formula ${v_d} = \frac{I}{nAe}$.Since the cross-sectional area $A$ and the charge $e$ are the same for both ele

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$5/4$

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(D) The drift velocity is given by the formula ${v_d} = \frac{I}{nAe}$.Since the cross-sectional area $A$ and the charge $e$ are the same for both electrons and holes,the ratio of drift velocities is given by:$\frac{(v_d)_e}{(v_d)_h} = \left( \frac{I_e}{I_h} ight) 	imes \left( \frac{n_h}{n_e} ight)$.Given that $\frac{n_e}{n_h} = \frac{7}{5}$,therefore $\frac{n_h}{n_e} = \frac{5}{7}$.Given that $\frac{I_e}{I_h} = \frac{7}{4}$.Substituting these values into the ratio formula:$\frac{(v_d)_e}{(v_d)_h} = \frac{7}{4} 	imes \frac{5}{7} = \frac{5}{4}$.

In a semiconductor,the ratio of the number of electrons to the number of holes is $7/5$ and the ratio of their currents is $7/4$. What is the ratio of their drift velocities?

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