In a common emitter configuration,an N-P-N tr | vedclass

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(B) Given: Current gain $\beta = 100$. Change in collector current $\Delta I_C = 1 \ mA$.We know that the relation between collector current and base

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$1.01$

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(B) Given: Current gain $\beta = 100$. Change in collector current $\Delta I_C = 1 \ mA$.We know that the relation between collector current and base current is $\Delta I_C = \beta \Delta I_B$.Therefore,the change in base current is $\Delta I_B = \frac{\Delta I_C}{\beta} = \frac{1 \ mA}{100} = 0.01 \ mA$.The relationship between emitter current,collector current,and base current is $\Delta I_E = \Delta I_C + \Delta I_B$.Substituting the values: $\Delta I_E = 1 \ mA + 0.01 \ mA = 1.01 \ mA$.Thus,the emitter current changes by $1.01 \ mA$.

In a common emitter configuration,an $N-P-N$ transistor is connected. The current gain of the transistor is $100$. If the collector current changes by $1 \ mA$,by how much will the emitter current change in $mA$?

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