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(A) $1$. Analyze the circuit from left to right. The two capacitors of capacitance $C$ and $C$ at the bottom left are in parallel. Their equivalent ca

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$3 C$

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(A) $1$. Analyze the circuit from left to right. The two capacitors of capacitance $C$ and $C$ at the bottom left are in parallel. Their equivalent capacitance is $C_{p1} = C + C = 2 C$.$2$. This $2 C$ is in series with the $2 C$ capacitor above it. The equivalent capacitance of this series branch is $C_{s1} = \frac{2 C 	imes 2 C}{2 C + 2 C} = \frac{4 C^2}{4 C} = C$.$3$. Now,this $C$ is in parallel with the other $C$ capacitor in the middle. Their equivalent capacitance is $C_{p2} = C + C = 2 C$.$4$. This $2 C$ is in series with the top $2 C$ capacitor. The equivalent capacitance of this branch is $C_{s2} = \frac{2 C 	imes 2 C}{2 C + 2 C} = C$.$5$. Finally,this $C$ is in parallel with the rightmost $2 C$ capacitor connected directly across $P$ and $Q$. The total equivalent capacitance is $C_{eq} = C + 2 C = 3 C$.

Find the equivalent capacitance between points $P$ and $Q$ in the combination shown in the figure.

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