The capacitance of a capacitor is $4 \times 10^{-6} \ F$ and it is charged to a potential difference of $100 \ V$. The energy required to completely discharge it is . . . . . . $J$.

If $C$ is the capacitance and $V$ is the electric potential,then the dimensional formula of $C V^{2}$ is

Two capacitors,each of value $10 \ \mu F$,are connected in parallel and charged to $200 \ V \ DC$. What is the energy stored in the combination in Joules?

The capacity of a capacitor is $4 \times 10^{-6} \, F$ and its potential is $100 \, V$. The energy released on discharging it fully will be ....... $J$.

The charge $q$ on a capacitor varies with voltage $V$ as shown in the figure. The area of the triangle $AOB$ represents:

$A$ parallel plate capacitor has plate area $A$ and separation between plates is $d$. It is charged to a potential difference of $V_0$ volt. The charging battery is then disconnected and plates are pulled apart to three times the initial distance. The work done to increase the distance between the plates is $(\varepsilon_0 = \text{permittivity of free space})$