In the steady state,what is the potential dif | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the steady state,no current flows through the capacitors. Therefore,the resistors in series with the capacitor network do not affect the potent

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) In the steady state,no current flows through the capacitors. Therefore,the resistors in series with the capacitor network do not affect the potential distribution across the capacitors.The total potential difference across the capacitor network between points $A$ and $C$ is $100 \ V$.From the simplified circuit diagram (as shown in the solution image),the capacitor branch $AB$ has a capacitance of $C_1 = 6 \ \mu F$ and the branch $BC$ has a capacitance of $C_2 = 2 \ \mu F$.Since the capacitors are in series,the potential difference across each capacitor is inversely proportional to its capacitance: $V \propto \frac{1}{C}$.Thus,$\frac{V_{AB}}{V_{BC}} = \frac{C_2}{C_1} = \frac{2 \ \mu F}{6 \ \mu F} = \frac{1}{3}$.This implies $V_{BC} = 3 V_{AB}$.Since $V_{AC} = V_{AB} + V_{BC} = 100 \ V$,we have $V_{AB} + 3 V_{AB} = 100 \ V$.$4 V_{AB} = 100 \ V$,which gives $V_{AB} = 25 \ V$.

In the steady state,what is the potential difference between points $A$ and $B$ in volts? (All capacitors are in $\mu F$.)

Similar Questions

In the circuit shown in the figure,four capacitors are connected to a battery. The potential difference across the $6 \ \mu F$ capacitor is......$V$.

In the electrical circuit shown below,the amount of charge stored in the capacitor is . . . . . . $\mu C$.

Four capacitors of capacitance $10\, \mu F$ and a battery of $200\, V$ are arranged as shown. How much charge will flow through $AB$ after the switch $S$ is closed?

In the following figure,the charge on each capacitor in the steady state will be.....$\mu C$.

Three point charges $1 \ C$,$-2 \ C$,and $-2 \ C$ are placed at the vertices of an equilateral triangle of side $1 \ m$. The work done by an external force to increase the separation of the charges to $2 \ m$ in joules is ($\varepsilon_0 =$ permittivity of air).

Vedclass Test Series

Exam Paper Generator

Online Exam Module