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(B) The energy stored in a fully charged capacitor is given by $U = \frac{1}{2}CV^2$,where $V$ is the potential difference across the capacitor.Since

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$\sqrt{\frac{2ms\Delta T}{C}}$

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(B) The energy stored in a fully charged capacitor is given by $U = \frac{1}{2}CV^2$,where $V$ is the potential difference across the capacitor.Since the capacitor is discharged through a resistance coil in a thermally insulated block,the entire electrical energy stored in the capacitor is converted into heat energy absorbed by the block.The heat energy absorbed by the block is given by $Q = ms\Delta T$.Equating the energy stored to the heat energy absorbed:$\frac{1}{2}CV^2 = ms\Delta T$$V^2 = \frac{2ms\Delta T}{C}$$V = \sqrt{\frac{2ms\Delta T}{C}}$

$A$ fully charged capacitor with capacitance $C$ is discharged through a small resistance coil embedded in a thermally insulated block of mass $m$ and specific heat $s$. If the temperature of the block increases by $\Delta T$,then the potential difference across the capacitor is:

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