What is the area of the plates of a capacitor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$.Rearranging the formula to solve for the are

Vedclass · Accepted Answer

$1.694 	imes 10^9 \ m^2$

Vedclass · Answer

(A) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$.Rearranging the formula to solve for the area $A$,we get $A = \frac{Cd}{\varepsilon_0}$.Given values are $C = 3 \ F$,$d = 5 \ mm = 5 	imes 10^{-3} \ m$,and $\varepsilon_0 = 8.85 	imes 10^{-12} \ F/m$.Substituting these values into the equation:$A = \frac{3 	imes 5 	imes 10^{-3}}{8.85 	imes 10^{-12}}$$A = \frac{15 	imes 10^{-3}}{8.85 	imes 10^{-12}}$$A \approx 1.694 	imes 10^9 \ m^2$.

What is the area of the plates of a capacitor with a capacitance of $3 \ F$? The distance between the two plates is $5 \ mm$.

Similar Questions

Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant $k$. The charge on each capacitor is $q$. Find the extension in the spring at equilibrium.

The unit of absolute permittivity is

In a parallel plate capacitor,the capacity can be increased by decreasing

The distance between the plates of a parallel plate capacitor is $4 \ mm$ and the potential difference is $60 \ V$. If the distance between the plates is increased to $12 \ mm$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module