The area of a cloud is 25 times 10^6 m^2 and | vedclass

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(D) The cloud and the earth form a parallel plate capacitor.The energy stored in the electric field is given by $U = \frac{1}{2} \epsilon_0 E^2 	imes

Vedclass · Accepted Answer

$1475$

Vedclass · Answer

(D) The cloud and the earth form a parallel plate capacitor.The energy stored in the electric field is given by $U = \frac{1}{2} \epsilon_0 E^2 	imes 	ext{Volume}$.Here, $E = \frac{V}{d}$, where $V = 10^5\ V$ and $d = 0.75\ km = 750\ m$.The volume of the space between the cloud and the earth is $V_{ol} = A 	imes d$, where $A = 25 	imes 10^6\ m^2$.Substituting these values into the energy formula:$U = \frac{1}{2} \epsilon_0 \left( \frac{V}{d} ight)^2 	imes (A 	imes d) = \frac{1}{2} \epsilon_0 \frac{V^2 A}{d}$.$U = \frac{1}{2} 	imes (8.85 	imes 10^{-12}) 	imes \frac{(10^5)^2 	imes 25 	imes 10^6}{750}$.$U = \frac{1}{2} 	imes 8.85 	imes 10^{-12} 	imes \frac{10^{10} 	imes 25 	imes 10^6}{750} = \frac{8.85 	imes 25 	imes 10^4}{1500} \approx 1475\ J$.

The area of a cloud is $25 \times 10^6\ m^2$ and the electric potential is $10^5\ V$. If the height of the cloud is $0.75\ km$, then the energy stored between the cloud and the earth is.....$J$

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