When a series combination of 2.0 mu F and 8.0 | vedclass

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(B) In a series combination,the charge $Q$ on each capacitor is the same.First,calculate the equivalent capacitance $C_{eq}$ for the two capacitors in

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$4.8 	imes 10^{-4}\ C$

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(B) In a series combination,the charge $Q$ on each capacitor is the same.First,calculate the equivalent capacitance $C_{eq}$ for the two capacitors in series:$C_{eq} = \frac{C_1 	imes C_2}{C_1 + C_2} = \frac{2.0 	imes 8.0}{2.0 + 8.0} \mu F = \frac{16}{10} \mu F = 1.6 \mu F$.The total charge $Q$ supplied by the source is given by $Q = C_{eq} 	imes V$.$Q = 1.6 	imes 10^{-6}\ F 	imes 300\ V = 480 	imes 10^{-6}\ C = 4.8 	imes 10^{-4}\ C$.Since the capacitors are in series,the charge on the $2.0\ \mu F$ capacitor is the same as the total charge $Q$,which is $4.8 	imes 10^{-4}\ C$.

When a series combination of $2.0\ \mu F$ and $8.0\ \mu F$ capacitors is connected to a $300\ V$ potential difference,the charge on the $2.0\ \mu F$ capacitor is .....

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